3+4*10^2x=63

Solution for 3+4*10^2x=63 equation:

3+4*10^2x=63

We move all terms to the left:

3+4*10^2x-(63)=0

We add all the numbers together, and all the variables

4*10^2x-60=0

Wy multiply elements

40x^2-60=0

a = 40; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·40·(-60)
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{6}}{2*40}=\frac{0-40\sqrt{6}}{80}
=-\frac{40\sqrt{6}}{80}
=-\frac{\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{6}}{2*40}=\frac{0+40\sqrt{6}}{80}
=\frac{40\sqrt{6}}{80}
=\frac{\sqrt{6}}{2}
$